Gcc template member function specialization




















Technical specifications. Flow control. Function declaration. Lambda function expression. Fundamental types. Function types. Compound types. Storage duration specifiers. Default initialization. Value initialization. Zero initialization.

Copy initialization. Direct initialization. Aggregate initialization. Constant initialization. Reference initialization. Value categories. Order of evaluation. Operator precedence. Alternative representations.

Boolean - Integer - Floating-point. Implicit conversions - Explicit conversions. Class declaration. Access specifiers. Virtual function. And the resolution also occurs at compile time. In this perspective, these two features look very similar. Therefore, it is only normal that you can achieve something equivalent to function template partial or total specialization with function overloading.

Either way, the execution will go through the specific implementation when you pass f a string. The same goes for partial specialization. Say we want a specific implementation of f for vectors.

Is this to say that there is no case for partial specialization on template functions? Overloading works for template arguments , which arguably represent a fair share of use cases for template functions. But what if the template is not in the argument? For instance, it could be in the return type of the function:. Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Collectives on Stack Overflow. Learn more. How to specialize template member function?

Ask Question. Asked 5 years, 11 months ago. Active 5 years, 11 months ago. Viewed 7k times. Improve this question. Patryk Patryk Function specialization is a regular function, not a template. As any other function, it must be declared in a header file and implemented in a source file; or else, implemented in a header file but marked inline. IgorTandetnik This approach works. You can submit it as an answer and I can accept it. Although I can define this method in the header file without inline.

Why is that so? I can define this method in the header file without inline Clearly you cannot, or you woudln't be here asking questions.



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